How to create a subaccount using Faraday's API

A short guide on creating a subaccount using Faraday's API.

How to create a subaccount using Faraday's API
Andy Rossmeissl
Andy Rossmeissl
on
1 min read

See our complete guide: Powered by Faraday — embedding predictive AI in your platform.


Our Powered by Faraday partners work with Faraday to supercharge their features with customer predictions, ensuring their customers receive the best solutions on the market.

To accomplish this goal, they need a subaccount for each of their customers so that all data is siloed and secure. In this guide, we'll walk through the steps to create a subaccount.

Finding your Faraday API key

The first thing you'll need in order to create a subaccount is your Faraday API key. You can find this in the Faraday Dashboard, under Settings in the left-hand nav, then Account. Click copy next to production environment.

Location of API key in Faraday's Dashboard

Creating a subaccount with the Faraday API

Next, head over to our API reference docs, and specifically the createAccount request.

Here, you'll want to do three things:

Arrows pointing to three steps to create a subaccount in Faraday's reference documentation

  1. First, paste your API key into the token field.
  2. Next, replace "Acme Wind Turbines" with the name you'd like to give your subaccount. We suggest something like "Your Company Name - Customer Company Name."
  3. Last, click send API request.

With these three steps done, your new subaccount will be accessible via the account switcher in the upper left corner of the Dashboard.

Location of account switcher in Faraday

Andy Rossmeissl

Andy Rossmeissl

Andy Rossmeissl is Faraday’s CEO and leads the product team in building the world’s leading context platform. An expert in the application of data analysis and machine learning to difficult business challenges, Andy has been running technology startups for almost 20 years. He attended Middlebury College and lives with his wife in Vermont where he lifts weights, makes music, and plays Magic: the Gathering.

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